Make a request to a web page, and return the status code:
import requests
x = requests.get('https://w3schools.com')
print(x.status_code)
The get() method sends a GET request to the specified url.
requests.get(url, params={key: value}, args)
args means zero or more of the named arguments in the parameter table below. Example:
requests.get(url, timeout=2.50)
Parameter Values Parameter Description url Try it Required. The url of the request params Try it Optional. A dictionary, list of tuples or bytes to send as a query string.None allow_redirects Try it Optional. A Boolean to enable/disable redirection.
True (allowing redirects) auth Try it Optional. A tuple to enable a certain HTTP authentication.
None cert Try it Optional. A String or Tuple specifying a cert file or key.
None cookies Try it Optional. A dictionary of cookies to send to the specified url.
None headers Try it Optional. A dictionary of HTTP headers to send to the specified url.
None proxies Try it Optional. A dictionary of the protocol to the proxy url.
None stream Try it Optional. A Boolean indication if the response should be immediately downloaded (False) or streamed (True).
False timeout Try it Optional. A number, or a tuple, indicating how many seconds to wait for the client to make a connection and/or send a response.
None which means the request will continue until the connection is closed verify Try it
True Return Value
The get() method returns a requests.Response object.
Track your progress - it's free!
RetroSearch is an open source project built by @garambo | Open a GitHub Issue
Search and Browse the WWW like it's 1997 | Search results from DuckDuckGo
HTML:
3.2
| Encoding:
UTF-8
| Version:
0.7.4