How to use variable arguments as an input when dealing with method overloading?
SolutionThis example displays how to overload methods which have variable arguments as an input.
public class Main { static void vaTest(int ... no) { System.out.print( "vaTest(int ...): " + "Number of args: " + no.length +" Contents: "); for(int n : no)System.out.print(n + " "); System.out.println(); } static void vaTest(boolean ... bl) { System.out.print( "vaTest(boolean ...) " + "Number of args: " + bl.length + " Contents: "); for(boolean b : bl)System.out.print(b + " "); System.out.println(); } static void vaTest(String msg, int ... no) { System.out.print( "vaTest(String, int ...): " + msg +"no. of arguments: "+ no.length +" Contents: "); for(int n : no) System.out.print(n + " "); System.out.println(); } public static void main(String args[]) { vaTest(1, 2, 3); vaTest("Testing: ", 10, 20); vaTest(true, false, false); } }Result
The above code sample will produce the following result.
vaTest(int ...): Number of args: 3 Contents: 1 2 3 vaTest(String, int ...): Testing: no. of arguments: 2 Contents: 10 20 vaTest(boolean ...) Number of args: 3 Contents: true false false
The following is an another sample example of varargs with method overloading.
public class Vararg { static void vararg(Integer... x) { System.out.println("Integer..."); } static void vararg(String... x) { System.out.println("String..."); } public static void main(String [] args) { int s = 0; vararg(s,s); } }
The above code sample will produce the following result.
Integer...
java_methods.htm
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