How to sort contents of a table?
SolutionFollowing example uses Order by SQL command to sort the table.
import java.sql.*; public class jdbcConn { public static void main(String[] args) throws Exception { Class.forName("org.apache.derby.jdbc.ClientDriver"); Connection con = DriverManager.getConnection ( "jdbc:derby://localhost:1527/testDb","name","pass"); Statement stmt = con.createStatement(); String query = "select * from emp order by name"; String query1 = "select * from emp order by name, job"; ResultSet rs = stmt.executeQuery(query); System.out.println("Table contents sorted by Name"); System.out.println("Id Name Job"); while (rs.next()) { int id = rs.getInt("id"); String name = rs.getString("name"); String job = rs.getString("job"); System.out.println(id + " " + name+" "+job); } rs = stmt.executeQuery(query1); System.out.println("Table contents after sorted by Name & job"); System.out.println("Id Name Job"); while (rs.next()) { int id = rs.getInt("id"); String name = rs.getString("name"); String job = rs.getString("job"); System.out.println(id + " " + name+" "+job); } } }Result
The above code sample will produce the following result. The result may vary.
Table contents after sorting by Name Id Name Job 1 ravi trainee 5 ravi MD 4 ravi CEO 2 ravindra CEO 2 ravish trainee Table contents after sorting by Name & job Id Name Job 4 ravi CEO 5 ravi MD 1 ravi trainee 2 ravindra CEO 2 ravish trainee
java_jdbc.htm
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