How to use catch to handle the exception?
SolutionThis example shows how to use catch to handle the exception.
public class Main{ public static void main (String args[]) { int array[] = {20,20,40}; int num1 = 15, num2 = 10; int result = 10; try { result = num1/num2; System.out.println("The result is" +result); for(int i = 5; i >= 0; i--) { System.out.println("The value of array is" +array[i]); } } catch (Exception e) { System.out.println("Exception occoured : "+e); } } }Result
The above code sample will produce the following result.
The result is1 Exception occoured : java.lang.ArrayIndexOutOfBoundsException: 5
The following is an another example of catch to handle the exception in Java
public class Trycatch { public static void main(String args[]) { try { int data = 50/0; } catch(ArithmeticException e){System.out.println(e);} System.out.println("rest of the code..."); } }
The above code sample will produce the following result.
java.lang.ArithmeticException: / by zero rest of the code...
java_exceptions.htm
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