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C Array of Pointers

Just like an integer array holds a collection of integer variables, an array of pointers would hold variables of pointer type. It means each variable in an array of pointers is a pointer that points to another address.

The name of an array can be used as a pointer because it holds the address to the first element of the array. If we store the address of an array in another pointer, then it is possible to manipulate the array using pointer arithmetic.

To create an array of pointers in C language, you need to declare an array of pointers in the same way as a pointer declaration. Use the data type then an asterisk sign followed by an identifier (array of pointers variable name) with a subscript ([]) containing the size of the array.

In an array of pointers, each element contains the pointer to a specific type.

The following example demonstrates how you can create and use an array of pointers. Here, we are declaring three integer variables and to access and use them, we are creating an array of pointers. With the help of an array of pointers, we are printing the values of the variables.

#include <stdio.h>

int main() {
  // Declaring integers
  int var1 = 1;
  int var2 = 2;
  int var3 = 3;

  // Declaring an array of pointers to integers
  int *ptr[3];

  // Initializing each element of
  // array of pointers with the addresses of
  // integer variables
  ptr[0] = &var1;
  ptr[1] = &var2;
  ptr[2] = &var3;

  // Accessing values
  for (int i = 0; i < 3; i++) {
    printf("Value at ptr[%d] = %d\n", i, *ptr[i]);
  }

  return 0;
}

When the above code is compiled and executed, it produces the following result −

Value of var[0] = 10
Value of var[1] = 100
Value of var[2] = 200

There may be a situation when we want to maintain an array that can store pointers to an "int" or "char" or any other data type available.

Here is the declaration of an array of pointers to an integer −

int *ptr[MAX];

It declares ptr as an array of MAX integer pointers. Thus, each element in ptr holds a pointer to an int value.

The following example uses three integers, which are stored in an array of pointers, as follows −

#include <stdio.h>
 
const int MAX = 3;
 
int main(){

   int var[] = {10, 100, 200};
   int i, *ptr[MAX];
 
   for(i = 0; i < MAX; i++){
      ptr[i] = &var[i]; /* assign the address of integer. */
   }
   
   for (i = 0; i < MAX; i++){
      printf("Value of var[%d] = %d\n", i, *ptr[i]);
   }
   
   return 0;
}

When the above code is compiled and executed, it produces the following result −

Value of var[0] = 10
Value of var[1] = 100
Value of var[2] = 200

You can also use an array of pointers to character to store a list of strings as follows −

#include <stdio.h>
 
const int MAX = 4;
 
int main(){

   char *names[] = {
      "Zara Ali",
      "Hina Ali",
      "Nuha Ali",
      "Sara Ali"
   };
   
   int i = 0;

   for(i = 0; i < MAX; i++){
      printf("Value of names[%d] = %s\n", i, names[i]);
   }
   
   return 0;
}

When the above code is compiled and executed, it produces the following result −

Value of names[0] = Zara Ali
Value of names[1] = Hina Ali
Value of names[2] = Nuha Ali
Value of names[3] = Sara Ali

When you have a list of structures and want to manage it using a pointer. You can declare an array of structures to access and manipulate the list of structures.

The below example demonstrates the use of an array of pointers to structures.

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

// Declaring a structure
typedef struct {
  char title[50];
  float price;
} Book;

const int MAX = 3;
int main() {
  Book *book[MAX];

  // Initialize each book (pointer)
  for (int i = 0; i < MAX; i++) {
    book[i] = malloc(sizeof(Book));
    snprintf(book[i]->title, 50, "Book %d", i + 1);
    book[i]->price = 100 + i;
  }

  // Print details of each book
  for (int i = 0; i < MAX; i++) {
    printf("Title: %s, Price: %.2f\n", book[i]->title, book[i]->price);
  }

  // Free allocated memory
  for (int i = 0; i < MAX; i++) {
    free(book[i]);
  }

  return 0;
}

When the above code is compiled and executed, it produces the following result −

Title: Book 1, Price: 100.00
Title: Book 2, Price: 101.00
Title: Book 3, Price: 102.00

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