Home - News ( United States | United Kingdom | Italy | Germany ) - Football scores

Showing content from https://www.tutorialspoint.com/cpp_standard_library/cpp_unordered_set_end.htm below:

C++ Unordered Set End Function

TheC++std::unordered_set::end() function is used to return an iterator pointing to the past-the-last element in the unordered_set container. The iterator returned does not point to any element but the position followed by the last element in the unordered_set container.

An iterator is an object (like a pointer) over elements that provides access to each individual element.

The unordered_set::end() function is similar to the unordered_set::cend() function, where the end() function returns only an iterator and the cend() function returns a const iterator.

Following is the syntax of std::unordered_set::end() function.

iterator end() noexcept;
const_iterator end() const noexcept;
or
local_iterator end (size_type n);
const_local_iterator end (size_type n) const;

• n − It indicates the bucket number that must be less than the bucket_count.

This function returns an iterator pointing to the position followed by the last element in the unordered_set container.

In the following example, we are going to use the loop inside the end() function and displaying the elements of the container in a range.

#include <iostream>
#include <string>
#include <unordered_set>

int main () {
   std::unordered_set<std::string> myUset =
      {"100","200","300","400","500"};
      
   std::cout << "myUset contains:";
   for ( auto it = myUset.begin(); it != myUset.end(); ++it )
      std::cout << " " << *it;
   std::cout << std::endl;
   
   return 0;
}

If we run the above code it will generate the following output −

myUset contains: 500 400 300 200 100

Consider the following example, where we are going to use the end() function that accepts i as a parameter and return the element of each bucket.

#include <iostream>
#include <string>
#include <unordered_set>

int main () {
   std::unordered_set<std::string> myUset = {"100", "200", "300", "400", "500"};
      
   std::cout << "myUset's buckets contain:\n";
   for ( unsigned i = 0; i < myUset.bucket_count(); ++i) {
      std::cout << "bucket #" << i << " contains:";
      for ( auto local_it = myUset.begin(i); local_it!= myUset.end(i); ++local_it )
         std::cout << " " << *local_it;
      std::cout << std::endl;
   }
   return 0;
}

Following is the output of the above code −

myUset's buckets contain:
bucket #0 contains:
bucket #1 contains: 400
bucket #2 contains: 500
bucket #3 contains:
bucket #4 contains: 100
bucket #5 contains:
bucket #6 contains:
bucket #7 contains:
bucket #8 contains:
bucket #9 contains:
bucket #10 contains: 300
bucket #11 contains: 200
bucket #12 contains:

Let's look at the following example, where we are going to use the end() function and getting the elements of the container by iterating over the unordered_set.

#include <iostream>
#include <unordered_set>  
#include <string> 
using namespace std;
 
int main() {
   unordered_set<int> myset = { 10,20,30,40,50 };  
      cout<<"Elements of myUset are: "<<endl;  
   unordered_set<int>::const_iterator it; // declare an iterator 
   it = myset.begin();
   while (it != myset.end()) {  
      cout << *it << "\n"; 
      ++it; // iterate to the next element  
   }  
   cout << endl;  
   return 0;
} 

Output of the above code is as follows −

Elements of myUset are: 
50
40
30
20
10

RetroSearch is an open source project built by @garambo | Open a GitHub Issue

Search and Browse the WWW like it's 1997 | Search results from DuckDuckGo

HTML: 3.2 | Encoding: UTF-8 | Version: 0.7.4