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Showing content from https://www.tutorialspoint.com/cpp_standard_library/cpp_stack_operator_assignment_move.htm below:

C++ Stack Operator Assignment and Move

The C++ function std::stack::operator= assigns new contents to the stack by replacing old ones. This method modifies size of the stack if necessary.

Following is the declaration for std::stack::operator= function form std::stack header.

stack<T, Container>& 
operator=( stack<T,Container>&& other );

x − Another stack object of same type.

Returns this pointer.

This member function never throws exception.

Linear i.e. O(n)

The following example shows the usage of std::stack::operator= function.

#include <iostream>
#include <stack>

using namespace std;

int main(void) {
   stack<int> s1;
   stack<int> s2;

   for (int i = 0; i < 5; ++i)
      s1.push(i + 1);

   cout << "Size of stack s1 before move operation = " << s1.size() << endl;

   s2 = move(s1);

   cout << "Size of stack s1 after move operation = " << s1.size() << endl;

   cout << "Contents of stack s2" << endl;
   while (!s2.empty()) {
      cout << s2.top() << endl;
      s2.pop();
   }

   return 0;
}

Let us compile and run the above program, this will produce the following result −

Size of stack s1 before move operation = 5
Size of stack s1 after move operation = 0
Contents of stack s2
5
4
3
2
1

stack.htm

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