The class used to represent and work with value arrays is called std::valarray. It provides a variety of generalized subscript operators, slicing, and indirect access in addition to element-wise mathematical operations.
The C++ Valarray::exp() function is used to compute e raised to the power of the value of the element in the valarray. Each element receives a single call to this method, which overloads with cmath's exp() function.
SyntaxFollowing is the syntax for C++ Valarray::exp Function −
exp (const valarray<T>& x);Parameters
x − It is containing elements of a type for which the unary function exp is defined.
Examples Example 1Let's look into the following example, where we are going to use exp() function and retrieving the output.
#include <iostream> #include <valarray> using namespace std; int main() { valarray<double> varr = { 4,6,8,10,11 }; valarray<double> varr1; varr1 = exp(varr); cout << "The New exp" << " Valarray is : " << endl; for (double& x : varr1) { cout << x << " "; } cout << endl; return 0; }Output
Let us compile and run the above program, this will produce the following result −
The New exp Valarray is : 54.5982 403.429 2980.96 22026.5 59874.1Example 2
Let's consider the following example, where we are going to use exp() function and retrieving the output with both original valarray and exp valarray.
#include <iostream> #include <valarray> using namespace std; int main() { valarray<double> myvalarray = { 1.2, -0.46, -1.5, 0.45, -1.23 }; cout << "The Orignal Valarray is : "; for (double& ele : myvalarray) cout << ele << " "; valarray<double> expValarray; expValarray = exp(myvalarray); cout << "\nThe exp Valarray is : "; for (double& ele : expValarray) cout << ele << " "; return 0; }Output
Let us compile and run the above program, this will produce the following result −
The Orignal Valarray is : 1.2 -0.46 -1.5 0.45 -1.23 The exp Valarray is : 3.32012 0.631284 0.22313 1.56831 0.292293Example 3
In the following example, we are going to consider the basic example of the usage of the exp() function.
#include <stdio.h> #include <math.h> int main () { double a, result; a = 2.3; result = exp (a); printf ("The exp value of %f is %f.\n", a, result ); return 0; }Output
Let us compile and run the above program, this will produce the following result −
The exp value of 2.300000 is 9.974182.
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