(PHP 4 >= 4.0.2, PHP 5, PHP 7, PHP 8)
get_resource_type — Returns the resource type
Parametersresource
The evaluated resource handle.
If the given resource is a resource, this function will return a string representing its type. If the type is not identified by this function, the return value will be the string Unknown.
This function will return null and generate an error if resource is not a resource.
Example #1 get_resource_type() example
<?php
$fp = fopen("foo", "w");
echo get_resource_type($fp) . "\n";
?>
Output of the above example in PHP 7:
CertaiN ¶11 years ago
Try this to know behavior:
<?php
function resource_test($resource, $name) {
echo
'[' . $name. ']',
PHP_EOL,
'(bool)$resource => ',
$resource ? 'TRUE' : 'FALSE',
PHP_EOL,
'get_resource_type($resource) => ',
get_resource_type($resource) ?: 'FALSE',
PHP_EOL,
'is_resoruce($resource) => ',
is_resource($resource) ? 'TRUE' : 'FALSE',
PHP_EOL,
PHP_EOL
;
}$resource = tmpfile();
resource_test($resource, 'Check Valid Resource');fclose($resource);
resource_test($resource, 'Check Released Resource');$resource = null;
resource_test($resource, 'Check NULL');
?>
It will be shown as...
[Check Valid Resource]
(bool)$resource => TRUE
get_resource_type($resource) => stream
is_resoruce($resource) => TRUE
[Check Released Resource]
(bool)$resource => TRUE
get_resource_type($resource) => Unknown
is_resoruce($resource) => FALSE
[Check NULL]
(bool)$resource => FALSE
get_resource_type($resource) => FALSE
Warning: get_resource_type() expects parameter 1 to be resource, null given in ... on line 10
is_resoruce($resource) => FALSE
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