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MySQL DENSE_RANK() Function By Practical Examples

Summary: in this tutorial, you will learn about the MySQL DENSE_RANK() function and how to apply it to find the rank of rows in a partition or result set.

The DENSE_RANK() is a window function that assigns a rank to each row within a partition or result set with no gaps in ranking values.

The rank of a row is increased by one from the number of distinct rank values that come before the row.

Here’s the basic syntax of the DENSE_RANK() function:

DENSE_RANK() OVER (
    PARTITION BY partition_expression
    ORDER BY sort_expression [ASC|DESC]
)Code language: SQL (Structured Query Language) (sql)

In this syntax:

• First, the PARTITION BY clause divides the result sets produced by the FROM clause into partitions. The DENSE_RANK() function is applied to each partition independently.
• Second, the ORDER BY  clause specifies the order of rows in each partition on which the DENSE_RANK() function operates.

If a partition has two or more rows with the same rank value, each of these rows will be assigned the same rank.

Unlike the RANK() function, the DENSE_RANK() function always returns consecutive rank values.

Suppose you have a table t with some sample data as follows:

CREATE TABLE t (
    val INT
);

INSERT INTO t(val)
VALUES(1),(2),(2),(3),(4),(4),(5);


SELECT * FROM t;Code language: SQL (Structured Query Language) (sql)

Output:

+------+
| val  |
+------+
|    1 |
|    2 |
|    2 |
|    3 |
|    4 |
|    4 |
|    5 |
+------+
7 rows in set (0.00 sec)Code language: JavaScript (javascript)

The following statement uses the DENSE_RANK() function to assign a rank to each row:

SELECT
    val,
    DENSE_RANK() OVER (
        ORDER BY val
    ) my_rank
FROM t;Code language: SQL (Structured Query Language) (sql)

Here is the output:

+------+---------+
| val  | my_rank |
+------+---------+
|    1 |       1 |
|    2 |       2 |
|    2 |       2 |
|    3 |       3 |
|    4 |       4 |
|    4 |       4 |
|    5 |       5 |
+------+---------+
7 rows in set (0.01 sec)Code language: JavaScript (javascript)

We will use the following sales table for the demonstration:

CREATE TABLE sales(
    sales_employee VARCHAR(50) NOT NULL,
    fiscal_year INT NOT NULL,
    sale DECIMAL(14,2) NOT NULL,
    PRIMARY KEY(sales_employee,fiscal_year)
);

INSERT INTO sales(sales_employee,fiscal_year,sale)
VALUES('Bob',2016,100),
      ('Bob',2017,150),
      ('Bob',2018,200),
      ('Alice',2016,150),
      ('Alice',2017,100),
      ('Alice',2018,200),
       ('John',2016,200),
      ('John',2017,150),
      ('John',2018,250);

SELECT * FROM sales;Code language: PHP (php)

Output:

+----------------+-------------+--------+
| sales_employee | fiscal_year | sale   |
+----------------+-------------+--------+
| Alice          |        2016 | 150.00 |
| Alice          |        2017 | 100.00 |
| Alice          |        2018 | 200.00 |
| Bob            |        2016 | 100.00 |
| Bob            |        2017 | 150.00 |
| Bob            |        2018 | 200.00 |
| John           |        2016 | 200.00 |
| John           |        2017 | 150.00 |
| John           |        2018 | 250.00 |
+----------------+-------------+--------+
9 rows in set (0.00 sec)Code language: JavaScript (javascript)

The following statement uses the DENSE_RANK() function to rank the sales employees by sale amount.

SELECT 
  sales_employee, 
  fiscal_year, 
  sale, 
  DENSE_RANK() OVER (
    PARTITION BY fiscal_year 
    ORDER BY sale DESC
  ) sales_rank 
FROM 
  sales;Code language: SQL (Structured Query Language) (sql)

The output is as follows:

In this example:

• First, the PARTITION BY clause divided the result sets into partitions using fiscal year.
• Second, the ORDER BY clause specified the order of the sales employees by sales in descending order.
• Third, the DENSE_RANK() function is applied to each partition with the order of the rows specified by the ORDER BY clause.

• Use the MySQL DENSE_RANK() function to rank rows in each partition of a result set.

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