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TypeScript Conditional Types - GeeksforGeeks

Last Updated : 24 Jan, 2025

In TypeScript, conditional types enable developers to create types that depend on a condition, allowing for more dynamic and flexible type definitions.

• They follow the syntax T extends U ? X : Y, meaning if type T is assignable to type U, the type resolves to X; otherwise, it resolves to Y.
• Conditional types are particularly useful for creating utility types and for advanced type manipulations, enhancing code reusability and type safety.

type IsString<T> = T extends string ? 'Yes' : 'No';

type Test1 = IsString<string>;
type Test2 = IsString<number>;

console.log('Test1:', 'Yes');
console.log('Test2:', 'No');

• The IsString type alias uses a conditional type to check if a type T extends the string.
• If T is assignable to string, it resolves to 'Yes'; otherwise, it resolves to 'No'.
• Test1 is evaluated as 'Yes' because the string extends the string.
• Test2 is evaluated as 'No' because the number does not extend the string.

Output:

Test1: Yes
Test2: No

type Num<T> = T extends number[] ? number 
    : (T extends string[] ? string : never)
    
// Return num
const num: Num<number[]> = 4;

// Return invalid
const stringnum: Num<number> = "7";

console.log(num, stringnum);

Conditional type constraints allow defining constraints on generic types within conditional types, enabling dynamic and precise type handling.

type CheckNum<T> = T extends number ? T : never;

type NumbersOnly<T extends any[]> = {
  [K in keyof T]: CheckNum<T[K]>;
};

const num: NumbersOnly<[4, 5, 6, 8]> = [4, 5, 6, 8];
const invalid: NumbersOnly<[4, 6, "7"]> = [4, 6, "7"];

• CheckNum<T> ensures only numbers are retained; other types resolve to never.
• NumbersOnly<T> applies CheckNum to each array element, filtering non-numbers.

Output:

Type '"7"' is not assignable to type 'never'.

This feature extracts and utilizes types within a conditional type definition, enabling precise transformations.

type ElementType<T> = T extends (infer U)[] ? U : never;

const numbers: number[] = [1, 2, 3];
const element: ElementType<typeof numbers> = numbers[0];
const invalidElement: ElementType<typeof numbers> = "string";

• ElementType<T> extracts element types from arrays using the infer keyword.
• element correctly resolves to number; assigning a string is invalid.

Output:

Type 'string' is not assignable to type 'number'.

These types distribute over unions, applying conditional logic to each union member individually.

type Colors = 'red' | 'blue' | 'green';

type ColorClassMap = {
  red: 'danger';
  blue: 'primary';
  green: 'success';
};

type MapColorsToClasses<T extends string> = T extends keyof ColorClassMap
  ? { [K in T]: ColorClassMap[T] }
  : never;

const redClass: MapColorsToClasses<Colors> = { red: 'danger' };
const invalidClass: MapColorsToClasses<Colors> = { yellow: 'warning' };

• MapColorsToClasses<T> checks if T matches a key in ColorClassMap, mapping it accordingly.
• Invalid colors like 'yellow' are rejected because they do not exist in ColorClassMap.

Output:

Type '{ yellow: "warning"; }' is not assignable to type 'never'.

• Use conditional types to create flexible, reusable type definitions.
• Combine conditional types with generics for enhanced adaptability.
• Utilize the infer keyword for type inference in complex scenarios.

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