A RetroSearch Logo

Home - News ( United States | United Kingdom | Italy | Germany ) - Football scores

Search Query:

Showing content from https://www.geeksforgeeks.org/tim-sort-in-python/ below:

Tim Sort in Python - GeeksforGeeks

Tim Sort in Python

Last Updated : 26 Feb, 2025

Tim Sort is a hybrid sorting algorithm derived from merge sort and insertion sort. It is designed to perform well on many kinds of real-world data. Tim Sort's efficiency comes from its ability to exploit the structure present in the data, such as runs (consecutive sequences that are already ordered) and merges these runs using a modified merge sort approach. It was Created by Tim Peters in 2002, Tim Sort is the default sorting algorithm in Python and is renowned for its speed and efficiency in real-world data scenarios.

How Tim Sort Works?

Let’s consider the following array as an example: arr[] = {4, 2, 8, 6, 1, 5, 9, 3, 7}.

Step 1: Define the size of the run

Step 2: Divide the array into runs

Step 3: Merge the runs

Step 4: Adjust the run size

Step 5: Continue merging

The final sorted array is [1, 2, 3, 4, 5, 6, 7, 8, 9].

Why Tim Sort is Efficient? Implementation:

Tim Sort is the default sorting algorithm in Python's sort() method for lists and sorted() function. Here's how you can use it:

Python
# Using the sort() method
a = [5, 3, 1, 4, 6, 2]
a.sort()
print("Sorted list using sort():", a)

# Using the sorted() function
a = [5, 3, 1, 4, 6, 2]
sorted_list = sorted(a)
print("Sorted list using sorted():", sorted_list)

Output
Sorted list using sort(): [1, 2, 3, 4, 5, 6]
Sorted list using sorted(): [1, 2, 3, 4, 5, 6]
Complete Implementation of Time Sort in Python

The Tim Sort algorithm first divides the input array into smaller segments of size min_run and performs an insertion sort on each segment. It then starts merging the sorted segments, doubling the merge size in each iteration until the entire array is merged.

The key steps are:

Code Example:

Python
def insertion_sort(arr, left=0, right=None):
    # Base case: if the array is already sorted, do nothing
    if right is None:
        right = len(arr) - 1

    # Iterate through the array, starting from the second element
    for i in range(left + 1, right + 1):
        # Select the current element
        key_item = arr[i]

        # Compare the current element with the previous one
        j = i - 1

        # While the previous element is greater than the current one,
        # shift the previous element to the next position
        while j >= left and arr[j] > key_item:
            arr[j + 1] = arr[j]
            j -= 1

        # Once the loop ends, the previous element is less than or equal to
        # the current element, so place the current element after it
        arr[j + 1] = key_item

    return arr


def merge(left, right):
    # If the left subarray is empty, return the right subarray
    if not left:
        return right

    # If the right subarray is empty, return the left subarray
    if not right:
        return left

    # Compare the first elements of the two subarrays
    if left[0] < right[0]:
        # If the first element of the left subarray is smaller,
        # recursively merge the left subarray with the right one
        return [left[0]] + merge(left[1:], right)
    else:
        # If the first element of the right subarray is smaller,
        # recursively merge the right subarray with the left one
        return [right[0]] + merge(left, right[1:])


def tim_sort(arr):
    # Initialize the minimum run size
    min_run = 32

    # Find the length of the array
    n = len(arr)

    # Traverse the array and do insertion sort on each segment of size min_run
    for i in range(0, n, min_run):
        insertion_sort(arr, i, min(i + min_run - 1, (n - 1)))

    # Start merging from size 32 (or min_run)
    size = min_run
    while size < n:
        # Divide the array into merge_size
        for start in range(0, n, size * 2):
            # Find the midpoint and endpoint of the left and right subarrays
            midpoint = start + size
            end = min((start + size * 2 - 1), (n - 1))

            # Merge the two subarrays
            merged_array = merge(arr[start:midpoint], arr[midpoint:end + 1])

            # Assign the merged array to the original array
            arr[start:start + len(merged_array)] = merged_array

        # Increase the merge size for the next iteration
        size *= 2

    return arr
  
  
 # Using the sorted() function
a = [5, 3, 1, 4, 6, 2]
sorted_list = tim_sort(a)
print("Sorted list using Tim Sort:", sorted_list)

Output
Sorted list using Tim Sort: [1, 2, 3, 4, 5, 6]

Time complexity: O(n log n) in the average and worst cases, making it an efficient sorting algorithm for large input arrays.
Auxiliary space: O(n) as the algorithm needs to create new arrays to store the merged results during the merge step.



RetroSearch is an open source project built by @garambo | Open a GitHub Issue

Search and Browse the WWW like it's 1997 | Search results from DuckDuckGo

HTML: 3.2 | Encoding: UTF-8 | Version: 0.7.4