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Python Program for cube sum of first n natural numbers

Last Updated : 23 Jul, 2025

We are given a number n and we need to print the sum of series 1³ + 2³ + 3³ + 4³ + .......+ n³ till the n-th term in python.

Examples:

Input: n = 5
Output: 225
Explanation: 1³ + 2³ + 3³ + 4³ + 5³ = 225

Let's discuss some of the ways to do it.

Most efficient solution is to use the direct mathematical formula which is (n ( n + 1 ) / 2) ^ 2, where n is the number of terms.

n = 5
res = ((n * (n + 1)) // 2) ** 2
print(res)

Explanation: ((n * (n + 1)) // 2) ** 2 gives us the sum of cubes of integers from 1 to n.

We can iterate from 1 to n, computing the cube of each number and summing them, where n is the limit up to which the sum is required.

n = 5
sum = 0

for i in range(1, n + 1):
    res += i ** 3

print(res)

Explanation: iterate from 1 to n using for loop and sum += i**3, keeps on adding the the cubes of the numbers.

Use generator expression to generate a list of cubes for numbers from 1 to n, then apply the sum() function to get the total. This approach is concise and efficient, combining iteration and summation in a single line.

n = 5

res = sum(i**3 for i in range(1, n + 1))

print(res)

Explanation: i**3 for i in range(1, n + 1) creates a list of cubes of numbers from 1 to n and then sum() function returns the sum of all the elements inside the list.

In this approach, we will use the enumerate list to find the cube sum of n natural numbers in one line.

n = 5
res = sum([(i+1) ** 3 for i, _ in enumerate(range(n))])
print(res)

Explanation:

• use list comprehension with enumerate(range(n)) to generate cubes of numbers from 1 to n.
• apply the sum() function to compute the total sum of cubes.
• underscore (_) in enumerate() is a throwaway variable since enumerate(range(n)) returns both index and value, but only the index (i) is used.

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