Last Updated : 14 Feb, 2023
The copy() method returns a shallow copy of the set in python. If we use "=" to copy a set to another set, when we modify in the copied set, the changes are also reflected in the original set. So we have to create a shallow copy of the set such that when we modify something in the copied set, changes are not reflected back in the original set. Syntax:
set_name.copy()
set_name: Name of the set whose copy
we want to generate.
Parameters:The copy() method for sets doesn't take any parameters. Return value:The function returns a shallow copy of the original set. Below is the implementation of the above function:
Python3
# Python3 program to demonstrate the use
# of join() function
set1 = {1, 2, 3, 4}
# function to copy the set
set2 = set1.copy()
# prints the copied set
print(set2)
Output:
{1, 2, 3, 4}
Time complexity : O(1),
space complexity: O(n)
Shallow Copy Example :
Python
# Python program to demonstrate that copy
# created using set copy is shallow
first = {'g', 'e', 'e', 'k', 's'}
second = first.copy()
# before adding
print 'before adding: '
print 'first: ',first
print 'second: ', second
# Adding element to second, first does not
# change.
second.add('f')
# after adding
print 'after adding: '
print 'first: ', first
print 'second: ', second
Output:
before adding: first: set(['s', 'e', 'k', 'g']) second: set(['s', 'e', 'k', 'g']) after adding: first: set(['s', 'e', 'k', 'g']) second: set(['s', 'e', 'k', 'g', 'f'])
Time complexity : O(1)
space complexity: O(n)
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