Last Updated : 12 Jul, 2025
Given a string s
, determine the number of substrings that satisfy certain criteria. For example we are given a string s="hellohellohello" we need to count how many time the substring occur in the given string suppose we need to find the substring "hello" so that the count becomes 3. We can use methods like count().
str.count()
count
()
method returns the number of non-overlapping occurrences of a substring in the string.
# Define the input string and the substring to count
s = "hellohellohello"
sub = "hello"
# Use the count() method to find the number of occurrences of the substring
c = s.count(sub)
print(c)
Explanation:
count()
method counts the number of non-overlapping occurrences of the substring "hello"
within the string s
.3
because the substring "hello"
appears three times in "hellohellohello"
.A for
loop can iterate through the string, using slicing to check for the occurrence of a substring. For example, using s[i:i+len(substring)]
inside the loop allows for comparing each slice of the string to the target substring
s1 = "hellohellohello"
sub = "hello"
# Initialize count to zero
cnt = 0
# Iterate through the string to check for the substring
for i in range(len(s) - len(sub) + 1):
if s[i:i + len(sub)] == sub: # If substring matches, increment count
cnt += 1
print(cnt)
Explanation:
for
loop iterates through the string s
, using slicing (s[i:i+len(substring)]
) to extract substrings of the same length as substring
and compare them.substring
, the count
is incremented, resulting in a count of 3
for the occurrences of "hello"
in "hellohellohello"
.Generate a list of indices where the substring starts and count its length.
Python
# Input string and substring to count
s = "hello world, hello universe"
sub = "hello"
# Count occurrences of the substring using a generator expression
c = sum(1 for i in range(len(s) - len(sub) + 1) if s[i:i + len(sub)] == sub)
print(c)
Explanation:
s
and counts matches of sub
with slices of s
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