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Showing content from https://www.geeksforgeeks.org/python/python-datetime-timedelta-class/ below:

Python DateTime - Timedelta Class

Last Updated : 22 Jul, 2022

Timedelta class is used for calculating differences between dates and represents a duration. The difference can both be positive as well as negative.

Syntax:

class datetime.timedelta(days=0, seconds=0, microseconds=0, milliseconds=0, minutes=0, hours=0, weeks=0)

Example:

Python3


 # Timedelta function demonstration

from datetime import datetime, timedelta

# creating datetime objects
date1 = datetime(2020, 1, 3)
date2 = datetime(2020, 2, 3)

# difference between dates
diff = date2 - date1
print("Difference in dates:", diff)

# Adding days to date1
date1 += timedelta(days = 4)
print("Date1 after 4 days:", date1)

# Subtracting days from date1
date1 -= timedelta(15)
print("Date1 before 15 days:", date1)

Output

Difference in dates: 31 days, 0:00:00
Date1 after 4 days: 2020-01-07 00:00:00
Date1 before 15 days: 2019-12-23 00:00:00

Class Attributes:

Let's see the attributes provided by this class -

Attribute Name Description min minimum value of timedelta object is -999999999 max maximum value of timedelta object is 999999999 resolution The minimum possible difference between timedelta objects

Example: Getting the minimum and maximum value of timedelta objects

Python3


 from datetime import timedelta

# Getting minimum value
Min = timedelta.min
print("Minimum value of timedelta object", Min)

# Getting minimum value
Max = timedelta.max
print("Maximum value of timedelta object", Max)

Output

Minimum value of timedelta object -999999999 days, 0:00:00
Maximum value of timedelta object 999999999 days, 23:59:59.999999

Output

Minimum value of timedelta object -999999999 days, 0:00:00

Maximum value of timedelta object 999999999 days, 23:59:59.999999

Class Functions

Timedelta class provides only one function which is total_seconds(). This method returns the duration provided by the timedelta object in the number of seconds.

Note: For a duration of more than 270 years this method will be accurate for microseconds.

Example: Getting various duration in seconds

Python3


 from datetime import timedelta

# Getting minimum value
obj = timedelta(hours=1)
print(obj.total_seconds())

obj = timedelta(minutes=1)
print(obj.total_seconds())

obj = timedelta(days=1)
print(obj.total_seconds())

Output

3600.0
60.0
86400.0

Operations supported by Timedelta Class Operator Description Addition (+) Adds and returns two timedelta objects Subtraction (-) Subtracts and returns two timedelta objects Multiplication (*) Multiplies timedelta object with float or int Division (/) Divides the timedelta object with float or int Floor division (//) Divides the timedelta object with float or int and return the int of floor value of the output Modulo (%) Divides two timedelta object and returns the remainder +(timedelta) Returns the same timedelta object -(timedelta) Returns the resultant of -1*timedelta abs(timedelta) Returns the +(timedelta) if timedelta.days > 1=0 else returns -(timedelta) str(timedelta) Returns a string in the form (+/-) day[s], HH:MM:SS.UUUUUU repr(timedelta) Returns the string representation in the form of the constructor call

Example 1: Performing basic arithmetic operations on timedelta objects.

Python3


 from datetime import timedelta

# creating the timedelta object
t1 = timedelta(days=1)
print("Original timedelta:", t1)

# multiplication
t2 = t1*5.5
print("After Multiplication:", t2)

# Subtraction
res = t2 - t1
print("After Subtraction:", res)

# addition
res += t2
print("After Addition:", res)

# division
res = t2/2.5
print("After division:", res)

# floor division
res = t2 //2
print("After floor division:", res)

# Modulo
res = t2%timedelta(days=3)
print("After Modulo:", res)

Output

Original timedelta: 1 day, 0:00:00
After Multiplication: 5 days, 12:00:00
After Subtraction: 4 days, 12:00:00
After Addition: 10 days, 0:00:00
After division: 2 days, 4:48:00
After floor division: 2 days, 18:00:00
After Modulo: 2 days, 12:00:00

Example 2: Getting Absolute value and the string representation of timedelta objects

Python3


 from datetime import timedelta

# creating the timedelta object
t1 = timedelta(days=1)
print("Original timedelta:", t1)

# Negation of timedelta object
t1 = -(t1)
print("After Negation:", t1)

# Getting Absolute value
t1 = abs(t1)
print("Absolute Value:", t1)

# Getting string representation
print("String representation:", str(t1))

# Getting Constructor call
print("Constructor call:", repr(t1))

Output

Original timedelta: 1 day, 0:00:00
After Negation: -1 day, 0:00:00
Absolute Value: 1 day, 0:00:00
String representation: 1 day, 0:00:00
Constructor call: datetime.timedelta(1)

Note: For more information on Python Datetime, refer to Python Datetime Tutorial

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