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Python | Count occurrences of an element in a Tuple

Last Updated : 03 Nov, 2022

In this program, we need to accept a tuple and then find the number of times an item is present in the tuple. This can be done in various ways, but in this article, we will see how this can be done using a simple approach and how inbuilt functions can be used to solve this problem. 

Examples:

Tuple: (10, 8, 5, 2, 10, 15, 10, 8, 5, 8, 8, 2)

Input : 4
Output : 0 times

Input : 10
Output : 3 times

Input : 8
Output : 4 times

Method 1(Simple Approach): 

We keep a counter that keeps on increasing if the required element is found in the tuple. 

# Program to count the number of times an element
# Present in the list


def countX(tup, x):
    count = 0
    for ele in tup:
        if (ele == x):
            count = count + 1
    return count


# Driver Code
tup = (10, 8, 5, 2, 10, 15, 10, 8, 5, 8, 8, 2)
enq = 4
enq1 = 10
enq2 = 8

print(countX(tup, enq))
print(countX(tup, enq1))
print(countX(tup, enq2))

Method 2(Using count()): 

The idea is to use method count() to count number of occurrences. 

# Program to count the number of times an element
# Present in the list
# Count function is used


def Count(tup, en):
    return tup.count(en)


# Driver Code
tup = (10, 8, 5, 2, 10, 15, 10, 8, 5, 8, 8, 2)
enq = 4
enq1 = 10
enq2 = 8
print(Count(tup, enq), "times")
print(Count(tup, enq1), "times")
print(Count(tup, enq2), "times")

0 times
3 times
4 times

Method 3: Using list comprehension

tuple1 = (10, 8, 5, 2, 10, 15, 10, 8, 5, 8, 8, 2)
x = [i for i in tuple1 if i == 10]
print("the element 10 occurs", len(x), "times")

the element 10 occurs 3 times

Method #4: Using enumerate function

tuple1=(10, 8, 5, 2, 10, 15, 10, 8, 5, 8, 8, 2)
x=[i for a,i in enumerate(tuple1) if i==10] 
print("the element 10 occurs",len(x),"times")

the element 10 occurs 3 times

Method #5: Using lambda function

tuple1=(10, 8, 5, 2, 10, 15, 10, 8, 5, 8, 8, 2)
x=list(filter(lambda i: (i==10),tuple1))
print("the element 10 occurs",len(x),"times")

the element 10 occurs 3 times

Method #6: Using counter function

from collections import Counter
tuple1=("10", "8", "5", "2", "10", "15", "10", "8", "5", "8", "8", "2") 
x=Counter(tuple1) 
print("the element 10 occurs",x["10"],"times")

the element 10 occurs 3 times

Method#7: Using Countof function

tuple1=("10", "8", "5", "2", "10", "15", "10", "8", "5", "8", "8", "2") 

import operator as op

print(op.countOf(tuple1,"10"))

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