Last Updated : 08 Mar, 2024
numpy.arccos(x[, out]) = ufunc 'arccos') :This mathematical function helps user to calculate inverse cos for all x(being the array elements).
Parameters :array : [array_like]elements are in radians. out : [array_like]array of same shape as x.
Note : 2pi Radians = 360 degrees The convention is to return the angle z whose real part lies in [0, pi].Return :
An array with inverse cosine of x for all x i.e. array elements. The values are in the closed interval [-pi/2, pi/2].Code #1 : Working Python3
# Python program explaining
# arccos() function
import numpy as np
in_array = [0, 1, 0.3, -1]
print ("Input array : \n", in_array)
arccos_Values = np.arccos(in_array)
print ("\nInverse Cosine values : \n", arccos_Values)
Output :
Input array : [0, 1, 0.3, -1] Inverse Cosine values : [ 1.57079633 0. 1.26610367 3.14159265]Code #2 : Graphical representation Python3
# Python program showing
# Graphical representation
# of arccos() function
import numpy as np
import matplotlib.pyplot as plt
in_array = np.linspace(-np.pi, np.pi, 12)
out_array1 = np.cos(in_array)
out_array2 = np.arccos(in_array)
print("in_array : ", in_array)
print("\nout_array with cos : ", out_array1)
print("\nout_arraywith arccos : ", out_array1)
# red for numpy.arccos()
plt.plot(in_array, out_array1,
color = 'blue', marker = "*")
plt.plot(in_array, out_array2,
color = 'red', marker = "o")
plt.title("blue : numpy.cos() \nred : numpy.arccos()")
plt.xlabel("X")
plt.ylabel("Y")
plt.show()
Output :
in_array : [-3.14159265 -2.57039399 -1.99919533 -1.42799666 -0.856798 -0.28559933 0.28559933 0.856798 1.42799666 1.99919533 2.57039399 3.14159265] out_array with cos : [-1. -0.84125353 -0.41541501 0.14231484 0.65486073 0.95949297 0.95949297 0.65486073 0.14231484 -0.41541501 -0.84125353 -1. ] out_arraywith arccos : [-1. -0.84125353 -0.41541501 0.14231484 0.65486073 0.95949297 0.95949297 0.65486073 0.14231484 -0.41541501 -0.84125353 -1. ] RuntimeWarning: invalid value encountered in arccos out_array1 = np.sin(in_array)
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