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Rounding off errors in Java

Last Updated : 05 Jul, 2024

Compacting many infinite real numbers into a finite number of bits requires an approximate representation. Most programs store the result of integer computations at 32 or 64 bits max. Given any fixed number of bits, most calculations with real numbers will produce quantities that cannot be exactly represented using that many bits. Therefore the result of a floating-point calculation must often be rounded to fit back into its finite representation. This rounding error is a characteristic feature of floating-point computation. Therefore, while handling calculations in floating point numbers, (especially if calculations are in terms of money), we need to take care of round-off errors in a programming language. Let's see an example:

public class Main {
    public static void main(String[] args)
    {
        double a = 0.7;
        double b = 0.9;
        double x = a + 0.1;
        double y = b - 0.1;

        System.out.println("x = " + x);
        System.out.println("y = " + y );
        System.out.println(x == y);
    }
}

Output:

x = 0.7999999999999999
y = 0.8
false

Here, the answer is not what we expected reason being the rounding off done by java compiler.

Float and Double data types implement IEEE floating point 754 specification. This means that numbers are represented in a form like:

SIGN FRACTION * 2 ^ EXP 

0.15625 = (0.00101)₂, which in floating-point format is represented as: 1.01 * 2^-3
Not all fractions can be represented exactly as a fraction of a power of two. As a simple example, 0.1 = (0.000110011001100110011001100110011001100110011001100110011001… )₂ and thus cannot be stored inside a floating-point variable.

Another Example:

public class Main {
    public static void main(String[] args)
    {
        double a = 0.7;
        double b = 0.9;
        double x = a + 0.1;
        double y = b - 0.1;

        System.out.println("x = " + x);
        System.out.println("y = " + y );
        System.out.println(x == y);
    }
}

Output:

x = 0.7999999999999999
y = 0.8
false

Another example:

public class Main {
    public static void main(String args[])
    {
        double a = 1.0;
        double b = 0.10;
        double x = 9 * b;
        a = a - (x);

        // Value of a is expected as 0.1
        System.out.println("a = " + a);
    }
}

Output:

a = 0.09999999999999998

• Round the result: The Round() function can be used to minimize any effects of floating point arithmetic storage inaccuracy. The user can round numbers to the number of decimal places that is required by the calculation. For example, while working with currency, you would likely round to 2 decimal places.
• Algorithms and Functions: Use numerically stable algorithms or design your own functions to handle such cases. You can truncate/round digits of which you are not sure they are correct (you can calculate numeric precision of operations too)
• BigDecimal Class: You may use the java.math.BigDecimal class, which is designed to give us accuracy especially in case of big fractional numbers. The following program shows how the error can be removed:

import java.math.BigDecimal;
import java.math.RoundingMode;

public class Main {
    public static void main(String args[]) {
        BigDecimal a = new BigDecimal("1.0");
        BigDecimal b = new BigDecimal("0.10");
        BigDecimal x = b.multiply(new BigDecimal("9"));
        a = a.subtract(x);

        // Rounding to 1 decimal place
        a = a.setScale(1, RoundingMode.HALF_UP);

        System.out.println("a = " + a);
    }
}

Output:

0.1

Here, a = a.setScale(1, RoundingMode.HALF_UP);

Rounds a to 1 decimal place using HALF_UP rounding mode. So, using BigDecimal provides more precise control over the arithmetic and rounding operations, which can be particularly useful for financial calculations or other cases where precision is crucial.

Math.round rounds the value to the nearest integer. As 0.10 is closer to 0 than to 1, it gets rounded to 0. After the rounding and division by 1.0, the result is 0.0. So you can notice the difference between the outputs with BigDecimal class and Maths.round function.

public class Main {
    public static void main(String args[])
    {
        double a = 1.0;
        double b = 0.10;
        double x = 9 * b;
        a = a - (x);

    /* We use Math.round() function to round the answer to
         closest long, then we multiply and divide by 1.0 to
         to set the decimal places to 1 place (this can be done
         according to the requirements.*/
        System.out.println("a = " + Math.round(a*1.0)/1.0);
    }
}

Output:

0.0

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