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Showing content from https://stackoverflow.com/questions/476436/is-there-a-null-coalescing-operator-in-javascript below:

Is there a "null coalescing" operator in JavaScript?

Nobody has mentioned in here the potential for NaN, which--to me--is also a null-ish value. So, I thought I'd add my two-cents.

For the given code:

var a,
    b = null,
    c = parseInt('Not a number'),
    d = 0,
    e = '',
    f = 1
;

If you were to use the || operator, you get the first non-false value:

var result = a || b || c || d || e || f; // result === 1

If you use the new ?? (null coalescing) operator, you will get c, which has the value: NaN

vas result = a ?? b ?? c ?? d ?? e ?? f; // result === NaN

Neither of these seem right to me. In my own little world of coalesce logic, which may differ from your world, I consider undefined, null, and NaN as all being "null-ish". So, I would expect to get back d (zero) from the coalesce method.

If anyone's brain works like mine, and you want to exclude NaN, then this custom coalesce method (unlike the one posted here) will accomplish that:

function coalesce() {
    var i, undefined, arg;

    for( i=0; i < arguments.length; i++ ) {
        arg = arguments[i];
        if( arg !== null && arg !== undefined
            && (typeof arg !== 'number' || arg.toString() !== 'NaN') ) {
            return arg;
        }
    }
    return null;
}

For those who want the code as short as possible, and don't mind a little lack of clarity, you can also use this as suggested by @impinball. This takes advantage of the fact that NaN is never equal to NaN. You can read up more on that here: Why is NaN not equal to NaN?

function coalesce() {
    var i, arg;

    for( i=0; i < arguments.length; i++ ) {
        arg = arguments[i];
        if( arg != null && arg === arg ) { //arg === arg is false for NaN
            return arg;
        }
    }
    return null;
}

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