FIRST, A CORRECTION TO THE OR CONDITIONAL:
You need to say:
if x == 0 or y == 0 or z == 0:
The reason is that "or" splits up the condition into separate logical parts. The way your original statement was written, those parts were:
x
y
z == 0 // or 1, 2, 3 depending on the if statement
The last part was fine --- checking to see if z == 0, for instance --- but the first two parts just said essentially if x and if y. Since integers always evaluate to True unless they're 0, that means the first part of your condition was always True when x or y didn't equal 0 (which in the case of y was always, since you had y = 1, causing your whole condition (because of how OR works) to always be True.
To avoid that, you need to make sure all parts of your condition (each side of the OR) make sense on their own (you can do that by pretending that the other side(s) of the OR statement doesn't exist). That's how you can confirm whether or not your OR condition is correctly defined.
You would write the statements individually like so:
if x == 0
if y == 0
if z == 0
which means the correct mergin with the OR keyword would be:
if x == 0 or y == 0 or z == 0
SECOND, HOW TO SOLVE THE PROBLEM:
You're basically wanting to check to see if any of the variables match a given integer and if so, assign it a letter that matches it in a one-to-one mapping. You want to do that for a certain list of integers so that the output is a list of letters. You'd do that like this:
def func(x, y, z):
result = []
for integer, letter in zip([0, 1, 2, 3], ['c', 'd', 'e', 'f']):
if x == integer or y == integer or z == integer:
result.append(letter)
return result
Similarly, you could use LIST COMPREHENSION to achieve the same result faster:
def func(x, y, z):
return [
letter
for integer, letter in zip([0, 1, 2, 3], ['c', 'd', 'e', 'f'])
if x == integer or y == integer or z == integer
]
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