Calculate slice bound that corresponds to given label.
Returns leftmost (one-past-the-rightmost if side=='right'
) position of given label.
Index of label.
See also
Index.get_loc
Get integer location, slice or boolean mask for requested label.
Examples
>>> idx = pd.RangeIndex(5) >>> idx.get_slice_bound(3, 'left') 3
>>> idx.get_slice_bound(3, 'right') 4
If label
is non-unique in the index, an error will be raised.
>>> idx_duplicate = pd.Index(['a', 'b', 'a', 'c', 'd']) >>> idx_duplicate.get_slice_bound('a', 'left') Traceback (most recent call last): KeyError: Cannot get left slice bound for non-unique label: 'a'
RetroSearch is an open source project built by @garambo | Open a GitHub Issue
Search and Browse the WWW like it's 1997 | Search results from DuckDuckGo
HTML:
3.2
| Encoding:
UTF-8
| Version:
0.7.4