Return the left endpoints of each Interval in the IntervalArray as an Index.
>>> interv_arr = pd.arrays.IntervalArray([pd.Interval(0, 1), pd.Interval(2, 5)]) >>> interv_arr <IntervalArray> [(0, 1], (2, 5]] Length: 2, dtype: interval[int64, right] >>> interv_arr.left Index([0, 2], dtype='int64')
RetroSearch is an open source project built by @garambo | Open a GitHub Issue
Search and Browse the WWW like it's 1997 | Search results from DuckDuckGo
HTML:
3.2
| Encoding:
UTF-8
| Version:
0.7.4