Return a fixed frequency TimedeltaIndex with day as the default.
Left bound for generating timedeltas.
Right bound for generating timedeltas.
Number of periods to generate.
Frequency strings can have multiples, e.g. â5hâ.
Name of the resulting TimedeltaIndex.
Make the interval closed with respect to the given frequency to the âleftâ, ârightâ, or both sides (None).
Specify the desired resolution of the result.
Added in version 2.0.0.
Fixed frequency, with day as the default.
See also
date_range
Return a fixed frequency DatetimeIndex.
period_range
Return a fixed frequency PeriodIndex.
Notes
Of the four parameters start
, end
, periods
, and freq
, exactly three must be specified. If freq
is omitted, the resulting TimedeltaIndex
will have periods
linearly spaced elements between start
and end
(closed on both sides).
To learn more about the frequency strings, please see this link.
Examples
>>> pd.timedelta_range(start="1 day", periods=4) TimedeltaIndex(['1 days', '2 days', '3 days', '4 days'], dtype='timedelta64[ns]', freq='D')
The closed
parameter specifies which endpoint is included. The default behavior is to include both endpoints.
>>> pd.timedelta_range(start="1 day", periods=4, closed="right") TimedeltaIndex(['2 days', '3 days', '4 days'], dtype='timedelta64[ns]', freq='D')
The freq
parameter specifies the frequency of the TimedeltaIndex. Only fixed frequencies can be passed, non-fixed frequencies such as âMâ (month end) will raise.
>>> pd.timedelta_range(start="1 day", end="2 days", freq="6h") TimedeltaIndex(['1 days 00:00:00', '1 days 06:00:00', '1 days 12:00:00', '1 days 18:00:00', '2 days 00:00:00'], dtype='timedelta64[ns]', freq='6h')
Specify start
, end
, and periods
; the frequency is generated automatically (linearly spaced).
>>> pd.timedelta_range(start="1 day", end="5 days", periods=4) TimedeltaIndex(['1 days 00:00:00', '2 days 08:00:00', '3 days 16:00:00', '5 days 00:00:00'], dtype='timedelta64[ns]', freq=None)
Specify a unit
>>> pd.timedelta_range("1 Day", periods=3, freq="100000D", unit="s") TimedeltaIndex(['1 days', '100001 days', '200001 days'], dtype='timedelta64[s]', freq='100000D')
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