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Showing content from https://pandas.pydata.org/docs/dev/user_guide/../reference/api/pandas.Grouper.html below:

pandas.Grouper — pandas 3.0.0.dev0+2231.g4f2aa4d2be documentation

pandas.Grouper#
class pandas.Grouper(*args, **kwargs)[source]#

A Grouper allows the user to specify a groupby instruction for an object.

This specification will select a column via the key parameter, or if the level parameter is given, a level of the index of the target object.

If level is passed as a keyword to both Grouper and groupby, the values passed to Grouper take precedence.

Parameters:
*args

Currently unused, reserved for future use.

**kwargs

Dictionary of the keyword arguments to pass to Grouper.

Attributes

Returns:
Grouper or pandas.api.typing.TimeGrouper

A TimeGrouper is returned if freq is not None. Otherwise, a Grouper is returned.

Examples

df.groupby(pd.Grouper(key="Animal")) is equivalent to df.groupby('Animal')

>>> df = pd.DataFrame(
...     {
...         "Animal": ["Falcon", "Parrot", "Falcon", "Falcon", "Parrot"],
...         "Speed": [100, 5, 200, 300, 15],
...     }
... )
>>> df
   Animal  Speed
0  Falcon    100
1  Parrot      5
2  Falcon    200
3  Falcon    300
4  Parrot     15
>>> df.groupby(pd.Grouper(key="Animal")).mean()
        Speed
Animal
Falcon  200.0
Parrot   10.0

Specify a resample operation on the column ‘Publish date’

>>> df = pd.DataFrame(
...     {
...         "Publish date": [
...             pd.Timestamp("2000-01-02"),
...             pd.Timestamp("2000-01-02"),
...             pd.Timestamp("2000-01-09"),
...             pd.Timestamp("2000-01-16"),
...         ],
...         "ID": [0, 1, 2, 3],
...         "Price": [10, 20, 30, 40],
...     }
... )
>>> df
  Publish date  ID  Price
0   2000-01-02   0     10
1   2000-01-02   1     20
2   2000-01-09   2     30
3   2000-01-16   3     40
>>> df.groupby(pd.Grouper(key="Publish date", freq="1W")).mean()
               ID  Price
Publish date
2000-01-02    0.5   15.0
2000-01-09    2.0   30.0
2000-01-16    3.0   40.0

If you want to adjust the start of the bins based on a fixed timestamp:

>>> start, end = "2000-10-01 23:30:00", "2000-10-02 00:30:00"
>>> rng = pd.date_range(start, end, freq="7min")
>>> ts = pd.Series(np.arange(len(rng)) * 3, index=rng)
>>> ts
2000-10-01 23:30:00     0
2000-10-01 23:37:00     3
2000-10-01 23:44:00     6
2000-10-01 23:51:00     9
2000-10-01 23:58:00    12
2000-10-02 00:05:00    15
2000-10-02 00:12:00    18
2000-10-02 00:19:00    21
2000-10-02 00:26:00    24
Freq: 7min, dtype: int64
>>> ts.groupby(pd.Grouper(freq="17min")).sum()
2000-10-01 23:14:00     0
2000-10-01 23:31:00     9
2000-10-01 23:48:00    21
2000-10-02 00:05:00    54
2000-10-02 00:22:00    24
Freq: 17min, dtype: int64
>>> ts.groupby(pd.Grouper(freq="17min", origin="epoch")).sum()
2000-10-01 23:18:00     0
2000-10-01 23:35:00    18
2000-10-01 23:52:00    27
2000-10-02 00:09:00    39
2000-10-02 00:26:00    24
Freq: 17min, dtype: int64
>>> ts.groupby(pd.Grouper(freq="17min", origin="2000-01-01")).sum()
2000-10-01 23:24:00     3
2000-10-01 23:41:00    15
2000-10-01 23:58:00    45
2000-10-02 00:15:00    45
Freq: 17min, dtype: int64

If you want to adjust the start of the bins with an offset Timedelta, the two following lines are equivalent:

>>> ts.groupby(pd.Grouper(freq="17min", origin="start")).sum()
2000-10-01 23:30:00     9
2000-10-01 23:47:00    21
2000-10-02 00:04:00    54
2000-10-02 00:21:00    24
Freq: 17min, dtype: int64
>>> ts.groupby(pd.Grouper(freq="17min", offset="23h30min")).sum()
2000-10-01 23:30:00     9
2000-10-01 23:47:00    21
2000-10-02 00:04:00    54
2000-10-02 00:21:00    24
Freq: 17min, dtype: int64

To replace the use of the deprecated base argument, you can now use offset, in this example it is equivalent to have base=2:

>>> ts.groupby(pd.Grouper(freq="17min", offset="2min")).sum()
2000-10-01 23:16:00     0
2000-10-01 23:33:00     9
2000-10-01 23:50:00    36
2000-10-02 00:07:00    39
2000-10-02 00:24:00    24
Freq: 17min, dtype: int64

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