05.07.18 01:51, Victor Stinner пише: > == Pattern 1, straighforward == > > while True: > line = input.readline() > if not line: > break > ... > > IMHO here assingment expression is appropriate here. The code remains > straighfoward to read. > > while (line := input.readline()): > ... We already have an idiom for this: for line in input: ...
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