On Wed, Oct 12, 2016 at 12:51 AM, Paul Moore <p.f.moore at gmail.com> wrote: > On 11 October 2016 at 14:04, Elliot Gorokhovsky > <elliot.gorokhovsky at gmail.com> wrote: >> Right, that sounds good, but there's just one thing I don't understand >> that's keeping me from using it. Namely, I would define a benchmark list L >> in my setup, and then I would have code="F=FastList(L);F.fastsort()". The >> problem here is I'm measuring the constructor time along with the sort time, >> right, so wouldn't that mess up the benchmark? Or does timeit separate the >> times? > > That would mess up your times. Put F=FastList(L) in your setup. But then you're resorting an already-sorted list, which may well have different timings (it certainly does in timsort). ChrisA
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