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Sat Dec 10 07:18:22 EST 2016 · https://mail.python.org/pipermail/python-dev/2016-December/146934.html

> I believe that this 'derived work' is both a trademark and a license
> violation.  Clause 7 of the PSF License V. 2, as displayed by '>>>
> license()', explicitly denies permission to make derivative works that
> violate PSF Trademarks.  Perhaps Github and Infoworld should be
> informed also, but our lawyer can decide.
>
> "This License Agreement does not grant permission to use PSF
> trademarks ..."
>
> Perhaps that document should mention somewhere at the top that
> "Python" is a PSF Trademark for computer languages.
I am not a lawyer, but to my understanding, violating the trademark is
not a violation of the license. The fact that the license mention it
doesn't grant permission to use PSF trademarks doesn't mean that by
violating the trademark you also violate the license.

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[Python-Dev] Someons's put a "Python 2.8" on GitHub