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Mon Sep 21 11:05:34 CEST 2015 · https://mail.python.org/pipermail/python-dev/2015-September/141746.html

On 21 September 2015 at 17:21, Nathaniel Smith <njs at pobox.com> wrote:
> On Sep 21, 2015 12:15 AM, "Victor Stinner" <victor.stinner at gmail.com> wrote:
>>
>> Would it be too verbose to display two frames or more by default?
>> Maybe depending on the action (ex: only if the warning is emitted only
>> once).
>
> It's not just about how it gets displayed -- the frame that it gets
> "attributed" to is also used when comparing against the warnings filters to
> determine what action to take. What if stacklevel=1 makes it match a filter
> with action "ignore", and stacklevel=2 makes it match a filter with action
> "raise"?
>
> (This is a common example I've encountered in the context of wanting to set
> up CI tests so that if *my* code uses deprecated functionality then I want
> to fail the test so I notice, but if some library I'm using uses deprecated
> functionality internally then that's not my problem. This breaks down when
> the library makes the common error of issuing DeprecationWarnings with
> stacklevel=1, because that makes python think that they are deprecating
> themselves, not warning that I did something deprecated.)

As Victor notes, though, that's not the right default for *scripts*
that are issuing deprecation warnings to end users - there, they
really are deprecating themselves. It's also not the right default for
pretty much any warning other than DeprecationWarning - for those,
you're generally wanting to say "we hit this problematic code path",
not report anything about your caller.

Passing "stacklevel=2" for API deprecations is by no means obvious
though, so perhaps it makes sense to add a
"warnings.warn_deprecated(message)" function that's implemented as:

    def warn_deprecated(message, stacklevel=1):
        return warnings.warn(message, DeprecationWarning,
stacklevel=(2+stacklevel)).

Cheers,
Nick.

-- 
Nick Coghlan   |   ncoghlan at gmail.com   |   Brisbane, Australia

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[Python-Dev] Make stacklevel=2 by default in warnings.warn()