On 10/09/2013 03:57 AM, Joao S. O. Bueno wrote: > def a([b],/,**kw): > print (b) > > does calling "a(b=5)" should raise a TypeError, or put "5" in > """kw["b"]""" and leave > "b" as "undefined" ? The latter. This is how they are "similarly to *args and **kwargs": >>> def foo(*a, **kw): ... print(a, kw) ... >>> foo(a=3, kw=5) () {'kw': 5, 'a': 3} >>> //arry/ -------------- next part -------------- An HTML attachment was scrubbed... URL: <http://mail.python.org/pipermail/python-dev/attachments/20131009/4d9b0b96/attachment.html>
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