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Sat Feb 26 22:33:57 CET 2011 · https://mail.python.org/pipermail/python-dev/2011-February/108397.html

2011/2/26 Grigory Javadyan <grigory.javadyan at gmail.com>:
>>>> def f():
> ...     a = 42
> ...     def g():
> ...             nonlocal a
> ...             del a
> ...
> SyntaxError: can not delete variable 'a' referenced in nested scope
>
> Which looks weird, because the name is referenced in the _enclosed_
> scope, not the _enclosing_ scope. Is there a typo in the documentation
> or am I missing something?

Actually you can do that now 3.2+. I've now removed that sentence;.

-- 
Regards,
Benjamin

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[Python-Dev] Unbinding a name referenced by an enclosing scope