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Fri Apr 29 07:28:23 CEST 2011 · https://mail.python.org/pipermail/python-dev/2011-April/111103.html

Robert Kern wrote:
> On 4/28/11 8:44 PM, Steven D'Aprano wrote:
>> Greg Ewing wrote:
>>> Taking a step back from all this, why does Python allow
>>> NaNs to arise from computations *at all*?
>>
>> The real question should be, why does Python treat all NANs as 
>> signalling NANs
>> instead of quiet NANs? I don't believe this helps anyone.
> 
> Actually, Python treats all NaNs as quiet NaNs and never signalling NaNs.

Sorry, did I get that backwards? I thought it was signalling NANs that 
cause a signal (in Python terms, an exception)?

If I do x = 0.0/0 I get an exception instead of a NAN. Hence a 
signalling NAN.

-- 
Steven

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[Python-Dev] Not-a-Number