>>> date(2008, 1, 30) + monthdelta(1)
datetime.date(2008, 2, 29)
What would this loop would print?
for d in range(1, 32):
print date(2008, 1, d) + monthdelta(1)
I have this funny feeling that arithmetic using monthdelta wouldn't always
be intuitive.
Skip
RetroSearch is an open source project built by @garambo | Open a GitHub Issue
Search and Browse the WWW like it's 1997 | Search results from DuckDuckGo
HTML:
3.2
| Encoding:
UTF-8
| Version:
0.7.4