On Wed, Apr 8, 2009 at 2:44 AM, Mark Dickinson <dickinsm at gmail.com> wrote: > On Wed, Apr 8, 2009 at 7:13 AM, John Barham <jbarham at gmail.com> wrote: >> If you play around a bit it becomes clear that what set.pop() returns >> is independent of the insertion order: > > It might look like that, but I don't think this is > true in general (at least, with the current implementation): > >>>> foo = set([1, 65537]) >>>> foo.pop() > 1 >>>> foo = set([65537, 1]) >>>> foo.pop() > 65537 You wrote a program to find the two smallest ints that would have a hash collision in the CPython set implementation? I'm impressed. And by impressed I mean frightened. -Jack
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