At 08:57 PM 12/30/2008 -0600, skip at pobox.com wrote: > Phillip> At 02:32 PM 12/30/2008 -0800, Scott David Daniels wrote: > >> More trouble with the "just take the dirname": > >> > >> paths = ['/a/b/c', '/a/b/d', '/a/b'] > >> os.path.dirname(os.path.commonprefix([ > >> os.path.normpath(p) for p in paths])) > >> > >> give '/a', not '/a/b'. > > Phillip> ...because that's the correct answer. > >I don't understand. If you search for os.path.commonprefix at >codesearch.google.com you'll find uses like this: > > if os.path.commonprefix([basedir, somepath]) != basedir: > ... > >which leads me to believe that other people using the current function in >the real world would be confused by your interpretation. It never would've occurred to me to use it for that, versus checking for somepath.startswith(basedir+sep). The only thing I've ever used commonprefix for is to find the most-specific directory that contains all the specified paths. Never occurred to me that there was any other use for it, actually.
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