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Sat Jan 20 02:32:27 CET 2007 · https://mail.python.org/pipermail/python-dev/2007-January/070708.html

Probably because I tend not to know what I'm doing when numerics are
concerned. :-(

On 1/19/07, Raymond Hettinger <raymond.hettinger at verizon.net> wrote:
> I bumped into an oddity today:
>
>     6.0 // 0.001 != math.floor(6.0 / 0.001)
>
> In looking at Objects/floatobject.c, I was surprised to find that
> float_floor_division() is implemented in terms of float_divmod().  Does anyone
> know why it takes such a circuitous path?  I had expected something simpler and
> faster:
>
>      return PyFloat_FromDouble(floor(a/b));
>
>
> Raymond
>
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[Python-Dev] Floor division