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Sun Apr 16 05:26:43 CEST 2006 · https://mail.python.org/pipermail/python-dev/2006-April/063777.html

[Bill Janssen]
> Yeah, but you can't do more complicated expressions that way, like
>
>      any(lambda x: x[3] == "thiskey")

You're not making any sense.  The sequence argument is not listed and the lambda 
is unnecessary.  Try this instead:

     any(x[3] == 'thiskey' for x in seq)

> I think it makes a lot of sense for any and all to take optional
> predicate function arguments.

I think you don't understand what you already have to work with in Py2.5a -- a 
boolean expression in a genexp should always suffice -- no separate lambda based 
predicate function is ever required.

Raymond

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Showing content from https://mail.python.org/pipermail/python-dev/2006-April/063777.html below:

[Python-Dev] Any reason that any()/all() do not take apredicateargument?