Just van Rossum wrote: > I don't think that in general you want to fold multiple empty lines into > one. This would be my prefered regex: > > s = re.sub(r"\r\n?", "\n", s) > > Catches both DOS and old-style Mac line endings. Alternatively, you can > use s.splitlines(): > > s = "\n".join(s.splitlines()) + "\n" > > This also makes sure the string ends with a \n, which may or may not be > a good thing, depending on your application. s = s.replace("\r", "\n"["\n" in s:]) </F>
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