Michael Walter wrote:
> Yepyep, but *how* you declare types now? Can you quickly type the function
> def f(x): x.read()? without needing an interface interface x_of_f: def
> read(): pass or a decorator like @foo(x.read)? I've no idea what you
> mean, really :o)
Why would something like
def f(x):
x.read()
do any type checking at all?
Cheers,
Nick.
--
Nick Coghlan | ncoghlan at email.com | Brisbane, Australia
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