> Actually no. When str.parition() doesn't find the separator, you get s, > '', ''. > Yours would produce '', '', s. On not found, you would need to use > start==end==len(s). > You're right. Nevermind, then. > I will say the same > thing that I've said at least three times already (with a bit of an > expansion): > Thanks for the re-re-emphasis. -Tony
RetroSearch is an open source project built by @garambo | Open a GitHub Issue
Search and Browse the WWW like it's 1997 | Search results from DuckDuckGo
HTML:
3.2
| Encoding:
UTF-8
| Version:
0.7.4