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Mon May 17 11:56:08 EDT 2004 · https://mail.python.org/pipermail/python-dev/2004-May/044868.html

"Edward C. Jones" <edcjones at erols.com> wrote in message
news:40A8D37B.7030807 at erols.com...
> # In the code below, "a.__str__()" does not default to "a.__repr__() as
> # might be expected. It finds the "__str__" in the base class X. The
> # Reference Manual, section 3.3.1, says:
> #    If a class defines __repr__() but not __str__(), then __repr__() is
> #    also used when an 'informal' string representation of instances of
> #    that class is required.
> # If the reader is in lawyer mode, the documentation is correct.
> # Is the current behavior what was intended? What should the behavior be?
>
> class X(object):
>     def __str__(self):
>         return 'str for X'
>
>     def __repr__(self):
>         return 'repr for X'
>
> class A(X):
>     def __repr__(self):
>         return 'repr for A'
>
> #    __str__ = __repr__
>
> x = X()
> a = A()
> print x.__str__()
> print x.__repr__()
> print a.__str__()
> print a.__repr__()
>
>
>
>
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str does not default to repr if a base classhas str

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Showing content from https://mail.python.org/pipermail/python-dev/2004-May/044868.html below:

__str__ does not default to __repr__ if a base classhas __str__

str does not default to repr if a base classhas str