Raymond Hettinger writes:
> Feedback is requested for two prospective itertools:
>
> def count_elements(iterable):
> b = {}
> for elem in iterable:
> b[elem] = b.get(elem, 0) + 1
> return ((cnt, elem) for elem, cnt in b.iteritems())
Is the behavior of count_elements() exactly the same as
the given python equivalent when one (or more) of the
elements in the iterable is not hashable?
-- Michael Chermside
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