Paul Morrow wrote: > Bob Ippolito wrote: > >> >> On Aug 21, 2004, at 5:34 PM, Paul Morrow wrote: >> >>> Phillip J. Eby wrote: >>> >>>> At 05:15 PM 8/21/04 -0400, Paul Morrow wrote: >>>> >>>>> Christophe Cavalaria wrote: >>>>> >>>>>> can it be ? There's also the fact that it can't handle named >>>>>> parameters >>>>>> like a regular function call. You can't write that : >>>>>> def foo(): >>>>>> __decoration__ = (1,1,param=True) >>>>> >>>>> >>>>> >>>>> >>>>> As far as I know, we can't do that with the current decorator >>>>> proposals either. >>>> >>>> >>>> @decoration(1,1,param=True) >>>> def foo(whatever): >>>> pass >>> >>> >>> >>> Ok, then whatever changes you've made to the Python system to support >>> that would allow the same syntax to be used in what I'm suggesting. >>> >>> def foo(whatever): >>> __decoration__ = (1,1,param=True) >>> >>> def decoration(decoratedFunc, a, b, param=False): >>> __decorator__ = True >>> __version__ = '0.1' >>> # body of 'decoration' decorator function goes here... >> >> >> >> Congratulations, this by far the worst suggestion yet! I'm -Inf on >> this :) >> > > Thanks. > > >> @decoration(1,1,param=True) makes no changes whatsoever to the Python >> system. Everything after the @ is really just an expression. The @ >> just implies that the result of the next class or def gets put through >> the result of the @expression before it is thrown into the namespace. >> > > It seems that writing a decorator is going to be a bizarre experience. > In the example, I would need to write a function named 'decoration' that > returns a function that will recieve a function (foo) to be decorated > and then return a function. Does that sound about right? > > What would functions like 'decoration' typically look like? Could you > show a short code snippet? > Nevermind. I got wrapped around the axle. I get it now. Thanks.
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