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Sun Apr 18 23:12:47 EDT 2004 · https://mail.python.org/pipermail/python-dev/2004-April/044385.html

On Sun, Apr 18, 2004 at 10:37:28PM -0400, Raymond Hettinger wrote:
> [Christian Stork]
> > I wanted to do something like
> > 
> >     i = itertools.chain(list1, list2).index(elem)
> 
> I'm curious about what application needed to do this.

It's for a simulation of a peer-to-peer algorithm I'm working on.  The
lists are lists of peers and could potentially become _very_ large.
Therefore concatenation might not be cheap.

> > If I use the operator module it works just fine.
> > 
> >     i = operator.indexOf(itertools.chain(list1, list2), elem)
> 
> Nice solution.  It is general purpose, self-documenting, and efficient.

Thanks. :-)

-- 
Chris Stork   <>  Support eff.org!  <>   http://www.ics.uci.edu/~cstork/
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