Andrew Koenig wrote:
> > Why can't you do this?
> > foo =3D log.setdefault(r,'')
> > foo +=3D "test %d\n" % t
> You can do it, but it's useless!
I got bitten by the same problem some time ago. Please let me explain:
I needed to count words, using a dict, of course. So, in my first
enthusiasm, I wrote:
count =3D {}
for word in wordlist:
count.setdefault(word, 0) +=3D 1
This, as I soon realized, didn't work, exactly because ints are immutable=
.
So I tried a different track. No problem, I thought, in the new Python
object world, the native classes can be subclassed. I imagined I could
enhance the int class with an inc() method, thusly:
class Counter(int):
def inc(self):
# to be defined
self +=3D 1??
count =3D {}
for word in wordlist:
count.setdefault(word, Counter()).inc()
As you can see, I have a problem at the comment: how do I access the
inherited int value??? I realized that this also wasn't going to work,
either. I finally used the perhaps idiomatic
count =3D {}
for word in wordlist:
count[word] =3D count.get(word, 0) + 1
which of course is suboptimal, because the lookup is done twice. I decide=
d
not to implement a proper Counter class for memory efficiency reasons. Th=
e
code would have been simple:
class Counter:
def __init__(self):
self.n =3D 0
def inc(self):
self.n +=3D 1
def get(self):
return self.n
count =3D {}
for word in wordlist:
count.setdefault(word, Counter()).inc()
But to restate the core question: can class Counter be written as a subcl=
ass
of int?
Beat Bolli (please CC: me on replys, I'm not on the list)
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