Alex Martelli wrote: > On Friday 14 March 2003 04:42 pm, Christian Tismer wrote: ... >>And the key assumption for sorting things is that >>the things are sortable, which means there >>exists and order on the basic set. >>Which again suggests that list elements usually >>have something in common. > > If a list contains ONE complex number and no other number, > then the list can be sorted. By a similar argument, tuples of one element can be sorted and reversed, just by doing nothing :-) > If the list contains elements that having something in common, > by both being complex numbers, then it cannot be sorted. Sure it can, by supplying a compare function, which implements the particular sorting operation that you want. Perhaps you want to sort them by their abs value or something. (And then you probably will want a stable sort, which is meanwhile a nice fact thanks to Tim: >>> a=[1, 2, 2+2j, 3+1j, 1+3j, 3-3j, 3+1j, 1+3j] >>> a.sort(lambda x, y:cmp(abs(x), abs(y))) >>> a [1, 2, (2+2j), (3+1j), (1+3j), (3+1j), (1+3j), (3-3j)] >>> ) Complex just has no total order, which makes it impossible to provide a meaningful default ordering. > So, lists whose elements have LESS in common (by being of > widely different types) are more likely to be sortable than lists > some of whose elements have in common the fact of being > numbers (if one or more of those numbers are complex). I agree that my statement does not apply when putting non-sortable things into a list. But I don't believe that people are putting widely different types into a list in order to sort them. (Although there is an arbitrary order between strings and numbers, which I would drop in Python 2.4, too). chris -- Christian Tismer :^) <mailto:tismer@tismer.com> Mission Impossible 5oftware : Have a break! Take a ride on Python's Johannes-Niemeyer-Weg 9a : *Starship* http://starship.python.net/ 14109 Berlin : PGP key -> http://wwwkeys.pgp.net/ work +49 30 89 09 53 34 home +49 30 802 86 56 pager +49 173 24 18 776 PGP 0x57F3BF04 9064 F4E1 D754 C2FF 1619 305B C09C 5A3B 57F3 BF04 whom do you want to sponsor today? http://www.stackless.com/
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