[Noah Spurrier]
>> I write these little directory/file filters quite often. I have
>> come across this problem of renaming the directories you are
>> traversing before.
[Martin v. L=F6wis]
> I still can't understand why you can't use os.path.walk for that.
> Did you know that you can modify the list that is passed to the
> callback, and that walk will continue to visit the elements in the =
list?
Let's spell it out. Say the directory structure is like so:
a/
b/
c/
d/
e/
and we want to stick "x" at the end of each directory name. The firs=
t thing
the callback sees is
arg, "a", ["b", "e"]
The callback can rename b and e, and change the contents of the fname=
s list
to ["bx", "ex"] so that walk will find the renamed directories. Etc.
This works:
"""
import os
def renamer(arg, dirname, fnames):
for i, name in enumerate(fnames):
if os.path.isdir(os.path.join(dirname, name)):
newname =3D name + "x"
os.rename(os.path.join(dirname, name),
os.path.join(dirname, newname))
fnames[i] =3D newname # crucial!
os.path.walk('a', renamer, None)
"""
It's certainly less bother renaming bottom-up; this works too (given =
the
last walk() generator implementation I posted):
"""
import os
for root, dirs, files in walk('a', topdown=3DFalse):
for d in dirs:
os.rename(os.path.join(root, d),
os.path.join(root, d + 'x'))
"""
A possible surprise is that neither of these renames 'a'.
RetroSearch is an open source project built by @garambo | Open a GitHub Issue
Search and Browse the WWW like it's 1997 | Search results from DuckDuckGo
HTML:
3.2
| Encoding:
UTF-8
| Version:
0.7.4