Hello Tim! > Wow, yesterday's drugs haven't worn off yet <wink>. The details of this > explanation were partly full of beans. Let's consider a different regexp: [...] Thanks for explaining again, in a way I could understand. :-) > ^(a)?b\1$ > > Should that match > > b > > or not? Python and Perl say "no" today, because \1 refers to a group that > didn't match. Ir remains unclear to me whether Gustavo is saying it should, > but, if he is, that's too big a change, and > > ^(a?)b\1$ [...] I still think it should, because otherwise the "^(a)?b\1$" can never be used, and this expression will become "^((a)?)b\1$" if more than one character is needed. But since nobody agrees with me, and both languages are doing it that way, I give up. :-) Could you please reject the patch at SF? Thank you! -- Gustavo Niemeyer [ 2AAC 7928 0FBF 0299 5EB5 60E2 2253 B29A 6664 3A0C ]
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