On Mon, Jun 10 @ 09:41, Tim Peters wrote:
> If you have a *positive* long that would fit in a 32-bit unsigned int (which
> type Python doesn't have), and know you're running on a 32-bit box, and only
> want the same bit pattern in an int, you can do
>
> def toint32(long):
> if long & 0x80000000L:
> long -= 1L << 32
> return int(long)
>
> This also raises OverflowError if you're mistaken about it fitting in 32
> bits.
Whoops. That should have been a 0x8... in my example :)
At ny rate, I wish this function was available as a built-in. It
would be nice if I had some conversion function where python looked
at the highest bit and treated that as my word boundary to determine
whether the number is positive or not.
-- Mike
--
Michael Gilfix
mgilfix@eecs.tufts.edu
For my gpg public key:
http://www.eecs.tufts.edu/~mgilfix/contact.html
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