>>> help(weakref.ref)
Help on built-in function ref:
ref(...)
new(object[, callback]) -- create a weak reference to 'object';
when 'object' is finalized, 'callback' will be called and passed
a reference to 'object'.
^^^^^^^^^^^^^^^^^^^^^^^
This appears to be a lie, or at least misleadingly phrased, in Python
2.2.1:
>>> class Z: pass
...
>>> def dying(x): print x, 'is dying'
...
>>> z = Z()
>>> r = weakref.ref(z, dying)
>>> z = 1
<weakref at 9826f8; dead> is dying
It appears that it's a reference to the weakref object that's passed, not
the dying object itself.
What's the intention?
TIA,
Dave
+---------------------------------------------------------------+
David Abrahams
C++ Booster (http://www.boost.org) O__ ==
Pythonista (http://www.python.org) c/ /'_ ==
resume: http://users.rcn.com/abrahams/resume.html (*) \(*) ==
email: david.abrahams@rcn.com
+---------------------------------------------------------------+
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